If $3 L$ $3 L$ of a gas at room temperature exerts a pressure of $7 k P a$ $7 kPa$ on its container, what pressure will the gas exert if it the container's volume changes to $1 L$ $1 L$ ?

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Answer 1 · 2016-02-27T04:21:30

From the ideal gas law we have that

$P_{1} \cdot V_{1} = P_{2} \cdot V_{2} \Rightarrow P_{2} = \frac{P_{1} \cdot V_{1}}{V_{2}}$ $P_1*V_1=P_2*V_2=>P_2=(P_1*V_1)/(V_2)$

Hence

$P_{2} = \frac{3 \cdot 7 \cdot 10^{4}}{1} = 21 \cdot 10^{4} = 21 k P a$ $P_2=(3*7*10^4)/1=21*10^4=21kPa$

If 3L3 L of a gas at room temperature exerts a pressure of 7kPa7 kPa on its container, what pressure will the gas exert if it the container's volume changes to 1L1 L?