Question

How do you solve `log_2 x=1/3 log_2 27`?

Answer 1

x = 3

Explanation:

using`color(blue)" laws of logarithms "`

`• logx^n = nlogx hArr nlogx = logx^n`

`• log_bx = log_by rArr x = y`

hence : `log_2x = log_2 27^(1/3)`

now `27^(1/3) = root(3)27 = 3`

`rArr log_2x = log_2 3 rArr x = 3`