How do you normalize #<3, 2, 1>#? Physics 2D Motion Vector Operations 1 Answer P dilip_k Feb 27, 2016 divide the vector by #sqrt(3^2+2^2+1^2)=sqrt14# Answer link Related questions What are vectors used for? Why vectors cannot be added algebraically? How do we represent the magnitude of a vector in physics? How do you find the equation of a vector orthogonal to a plane? Why are vectors important? How does a vector quantity differ from a scalar quantity? How can I calculate the magnitude of vectors? How do vectors subtract graphically? How do force vectors affect an object in motion? How can vectors be represented? See all questions in Vector Operations Impact of this question 1233 views around the world You can reuse this answer Creative Commons License