What is the derivative of $arctan(x^2+1)$ ?

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Answer 1 · 2016-02-27T17:29:57

$(2x)/(1+(x^2+1)^2)$

From the rules, $d/dxtan^(-1)[u(x)]=1/(1+u^2)*(du)/dx$

we get

$d/dxtan^(-1)(x^2+1)=1/(1+(x^2+1)^2)*2x$

What is the derivative of arctan(x^2+1)arctan(x^2+1)?