Question

How do you solve `abs(5x+2)= 3`?

Answer 1

when `(5x+2)>0,`then`|5x+2|=3=>5x+2=3=>x=1/5`
when `(5x+2)<0,`then`|5x+2|=3=>-(5x+2)=3=>-5x=5=>x=-1`
`:. x=1/5`and `x=-1`