How do you simplify #7 + 14 - 3 +5 times 2^3# using PEMDAS?

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Answer 1 · 2016-02-28T08:45:59

#7+14-3+5xx2^3=color(blue)58#

#7+14-3+5xx2^3#

First we take care of the exponent.

#2^3=8#

Carry out the multiplication.

#5xx8=40#

Now add or subtract from left to right.

#7+14-3+40=58#

Answer 2 · 2016-02-28T09:14:33

ANSWER=58

P- parenthesis

E-exponents

M/D - multiplication / division (from left to right)

A/S - addition / subtraction (from left to right)

In any mathematical expression, the above order must be followed.

Given that,

#7+14-3+5xx2^3#

Let
#x=7+14-3+5xx2^3#

(1). There is no parenthesis in above expression.

(2).There is an exponent term in above expression.

#x=7+14-3+5xx8# [since #2^3=8#]

(3).There is a multiplication symbol in between 5 and 8.

#x=7+14-3+40#

(4)Reduce above expression to single number by adding and subtracting from left to right.

#x=21-3+40#

#x=18+40#

#x=58#