Question

What is the domain and range of `y =sqrt(17x+8)`?

Answer 1

Domain: `x>=-8/17` or Domain:`[-8/17, +oo)`
Range:`y>=0` or Range:`[0, +oo)`

Explanation:

The square root of a negative number is an imaginary number.
The square root of zero is zero. The radicand is zero at `x=-8/17`.
Any value greater than -8/17 will result to a positive radicand.
Therefore, Domain: `x>=-8/17`

Range: is 0 to +infinity

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