How do you find the derivative of # y=5/(x-3)^2#?

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Answer 1 · 2016-02-28T13:46:46

You can rewrite this as follows

#y=5(x-3)^-2#

Hence the first derivative is

#y'=5*(-2)*(x-3)^-3*(x-3)'=> y'=-[10]/(x-3)^3#

where #()'=d/dx#

Note :

The derivative of a function #[f(x)]^n# where n is an integer is

#n*[f(x)]^(n-1)*((df(x))/dx)#