How do you find the asymptotes for #f(x)=(x+7)/(x^2-49)#?

1 Answer
bp
Feb 29, 2016

Vertical asymptote is x=7 and
Horizontal asymptote is y=0, that is x axis

Explanation:

f(x)= #(x+7)/(x^2-49)= 1/(x-7)#

There is a vertical asymptote given by x-7=0 that is x=7.

Further, since the degree of the polynomial in the numerator is less than the degree of the polynomial in the denominator, there would be a horizontal asymptote y=0

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