How much work does it take to raise a #33 kg # weight #94 m #?

1 Answer
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Mar 1, 2016

#30 "kJ"#

Explanation:

The force required to overcome the weight of a #33 "kg"# object is

#F = mg#

#= (33 "kg") * (9.8 "m/s"^2)#

#= 323.4 "N"#

The work done to lift such an object up by #94 "m"# is the force exerted multiplied by the distance raised.

#W = F * d#

#= (323.4 "N") * (94 "m")#

#= 30400 "J"#

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