Question

What is the derivative of `g(x)=-3 root3 (2-9x)`?

Answer 1

`g'(x)=9(2-9x)^(-2/3)`

Explanation:

`g(x)=-3(2-9x)^(1/3)`

Applying the chain rule`rArr`

`g'(x)=-3[1/cancel(3)(2-9x)^(-2/3)xx-cancel(9)3]`

`:.g'(x)=-3[-3(2-9x)^(-2/3)]`

`:.g'(x)=9(2-9x)^(-2/3)`