Question

What is the perimeter of a triangle with corners at `(1 ,5 )`, `(8 ,3 )`, and `(4 ,1 )`?

Answer 1

Perimeter is `7.28+4.472+5=11.752`

Explanation:

To find the perimeter of a triangle with corners at `(1,5), (8,3)`, and `(4,1)`, we need the length of all sides of the triangle i.e. distance between each pair of points. Let the points be `A, B, C` respectively.

So `AB` is `sqrt((8-1)^2+(3-5)^2)=sqrt(7^2+(-2)^2)=sqrt(49+4)=sqrt53=7.28`

`BC` is `sqrt((8-4)^2+(3-1)^2)=sqrt(4^2+2^2)=sqrt(16+4)=sqrt20=4.472`

`CA` is `sqrt((1-4)^2+(5-1)^2)=sqrt((-3)^2+4^2)=sqrt(9+16)=sqrt25=5`

Hence perimeter is `7.28+4.472+5=11.752`