What is the perimeter of a triangle with corners at (1 ,5 ), (8 ,3 ), and (4 ,1 )?

1 Answer
Mar 2, 2016

Perimeter is 7.28+4.472+5=11.752

Explanation:

To find the perimeter of a triangle with corners at (1,5), (8,3), and (4,1), we need the length of all sides of the triangle i.e. distance between each pair of points. Let the points be A, B, C respectively.

So AB is sqrt((8-1)^2+(3-5)^2)=sqrt(7^2+(-2)^2)=sqrt(49+4)=sqrt53=7.28

BC is sqrt((8-4)^2+(3-1)^2)=sqrt(4^2+2^2)=sqrt(16+4)=sqrt20=4.472

CA is sqrt((1-4)^2+(5-1)^2)=sqrt((-3)^2+4^2)=sqrt(9+16)=sqrt25=5

Hence perimeter is 7.28+4.472+5=11.752