How do you find g(h(t)) given $g(t) = (t+1)/2$ , $h(t) = (t-3)/4$ ?

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Answer 1 · 2016-03-02T14:00:14

$g(h(t))=(t+1)/8$

Given: $g(t)=(t+1)/2$ and $h(t)=(t-3)/4$

$g(h(t))=(h(t)+1)/2=((t-3)/4+1)/2=(t-3+4)/8=(t+1)/8$

God bless...I hope the explanation is useful..

How do you find g(h(t)) given g(t) = (t+1)/2g(t) = (t+1)/2, h(t) = (t-3)/4h(t) = (t-3)/4?