Question

How do you find the derivative of `f(x)= (x^2-1)/x`?

Answer 1

`f=x^2-1,g=x->f'=2x,g'=1`
`f'(x)=((gf'-fg')/g^2)=(2x^2-x^2+1)/x^2=(x^2+1)/x^2`

Explanation:

Separate the top and bottom into f and g then find f' and g' and then put it in to the quotient rule