Question

How do you solve `x^2 - 6x + 4 = 0` using the quadratic formula?

Answer 1

`x = 3 +- sqrt5`

Explanation:

`y = x^2 - 6x + 4 = 0`
`D = d^2 = b^2 - 4ac = 36 - 16 = 20` --> `d = +- 2sqrt5`
`x = -b/(2a) +- d/(2a) = 6/2 +- (2sqrt5)/2 = 3 +- sqrt5`