Question

What are the mean and standard deviation of a binomial probability distribution with `n=11` and `p=7/30`?

Answer 1

Mean is `2.567` and Standard Deviation is `1.403`

Explanation:

For a binomial probability distribution with `n=11` and `p=7/30`

Mean is given by `np=11xx7/30=2.567`

Standard Deviation is given by `sqrt(npq)` where `q=1-p`

Hence, Standard Deviation is `sqrt(11xx7/30xx(1-7/30))`

= `sqrt(11xx7/30xx23/30`

= `(sqrt(11xx7xx23))/30` = `1.403`