Question

If an object with uniform acceleration (or deceleration) has a speed of `6 m/s` at `t=0` and moves a total of 4 m by `t=3`, what was the object's rate of acceleration?

Answer 1

`a=-28/9" "m/s^2`
`a=28/9 " "m/s^2`

Explanation:

`x=v_i*t+1/2*a*t^2`
`4=6*3+1/2*a*3^2`
`-28=9*a " "a=-28/9" "m/s^2`
`x=v_i*t-1/2*a*t^2`
`4=6*3-1/2*a*3^2`
`28=9*a" "a=28/9 " "m/s^2`