Question

If `24 L` of a gas at room temperature exerts a pressure of `72 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7 L`?

Answer 1

`P_2~=246,86 kPa`

Explanation:

`P_1*V_1=P_2*V_2`
`72*24=P_2*7`
`P_2=(72*24)/7`
`P_2~=246,86 kPa`