How do you solve $Log_a x - Log_a 2 = Log_a 9 + Log_a 8$ ?

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Answer 1 · 2016-03-06T15:32:08

$x=144$

$log_a( x/2)=log_a3^2+log_a2^3$
$log_a( x/2)=log_a(3^2*2^3)$
$x/2=3^2*2^3$
$x=3^2*2^4$
$x=9*16$
$x=144$

How do you solve Log_a x - Log_a 2 = Log_a 9 + Log_a 8Log_a x - Log_a 2 = Log_a 9 + Log_a 8?