Question

How do you find the derivative of `ln sqrt (x^2-4)`?

Answer 1

`d/dx (ln sqrt (x^2-4)) = x/(x^2-4)`

Explanation:

`ln sqrt (x^2-4) = 1/2 ln (x^2-4)`

Hence:

`[ln sqrt (x^2-4)]^' = [1/2 ln (x^2-4)]^'`
`=1/2 * (x^2-4)^'/(x^2-4) =1/2 * (2x)/(x^2-4) = x/(x^2-4)`