Question

A ball rolls with a speed of `2.0m/s` across a level table that is `1.0m` above the floor. Upon reaching the edge of the table, it follows a parabolic path to the floor. How far along the floor is the landing spot from the table?

Answer 1

We need to consider vertical and horizontal components.

Explanation:

If we consider the vertical component, we can determine how long the ball is in free fall. We can use:
`s=ut+1/2at^2`
S=1m
And u, initial velocity in vertical direction, is 0m/s
And we can take acceleration as 9.81 `ms^-2`
`1=1/2*9.8*t^2`

So t= 0.45s

In the horizontal direction, there is no acceleration so we can simply use `velocity= S/t`
Hence distance along the floor from the table is `2times0.45=0.9m`