A ball rolls with a speed of #2.0m/s# across a level table that is #1.0m# above the floor. Upon reaching the edge of the table, it follows a parabolic path to the floor. How far along the floor is the landing spot from the table?

1 Answer
Mar 8, 2016

We need to consider vertical and horizontal components.

Explanation:

If we consider the vertical component, we can determine how long the ball is in free fall. We can use:
#s=ut+1/2at^2#
S=1m
And u, initial velocity in vertical direction, is 0m/s
And we can take acceleration as 9.81 #ms^-2#
#1=1/2*9.8*t^2#

So t= 0.45s

In the horizontal direction, there is no acceleration so we can simply use #velocity= S/t#
Hence distance along the floor from the table is #2times0.45=0.9m#