How do you solve Log_2 32 = x?

2 Answers
Mar 9, 2016

x=5

Explanation:

The logarithmic expression can be exponentiated with a base of 2:

2^(log_2 32)=2^x

The 2^x and log_2 x functions are inverses, which means that they undo one another, so we obtain the equation:

32=2^x

We can write 32 as a power of 2:

2^5=2^x

Since the bases are equal, we know their powers are also equal, giving:

x=5

Mar 9, 2016

x=5

Explanation:

Since 32=2^5, we see that

log_2 2^5=x

Using the logarithm rule:

log(a^b)=b*log(a)

Giving the equation:

5*log_2 2=x

Since log_a a=1,

x=5