How do you solve Log_2 32 = x?
2 Answers
Mar 9, 2016
Explanation:
The logarithmic expression can be exponentiated with a base of
2^(log_2 32)=2^x
The
32=2^x
We can write
2^5=2^x
Since the bases are equal, we know their powers are also equal, giving:
x=5
Mar 9, 2016
Explanation:
Since
log_2 2^5=x
Using the logarithm rule:
log(a^b)=b*log(a)
Giving the equation:
5*log_2 2=x
Since
x=5