How do you solve #12/21= (x-5)/x#?

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Answer 1 · 2016-03-10T18:50:39

#x = 105/9 or 11(6)/9 or 11(2)/3#

#12/21 = (x-5)/x#

Cross multiply to eliminate the denominators.
#12(x) = (x-5)21#

Use distributive property to eliminate the ( ).
#12x = 21x - 105#

Combine like terms.
#12x - 21x = cancel(21x) - cancel(21x) - 105#

#-9x = -105#

Divide by the coefficient to isolate the variable.
#(cancel(-9)x)/cancel(-9) = -105/-9#

#x = 105/9 or 11(6)/9 or 11(2)/3#