Question

How do you graph the equation by plotting points `y = 2 sqrt (x) + 3`?

Answer 1

`x >=0. and y>=3`. The graph is semi-parabola `(y-3)^2=4x`. It is upper half, including vertex at (0, 3). Passes through (0, 3), (9, 9), (16, 11),...`(n^2, 2n+3)`, ......

Explanation:

Indeed, interesting.
Axis of the parabola is y = 3. Focus is (1, 3).
Note that the mirror image about y = 3 is given by
`y=-2sqrtx+3`