Question

A container with a volume of `18 L` contains a gas with a temperature of `250^o C`. If the temperature of the gas changes to `320 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

`V_2~=20,41" " L`

Explanation:

`V_1/T_1=V_2/T_2`
`"First; change " ^o C" to "^o K`
`T_1=250+273=523^o K`
`T_2=320+273=593^o K`
`"use Charles Law's above"`
`18/523=V_2/593`
`V_2=(593*18)/523`
`V_2~=20,41" " L`