Question

Question #8d154

Answer 1

`C=110^o`
https://en.wikipedia.org/wiki/Alcohol_thermometer

Explanation:

1. This problem is merely conversion from `F` to `C`;
2. I don't recommend memorizing the formula, but always remember the following data to accurately write the conversion formula for these temperature scales:

Boiling Pt of Water

`F=212^o`
`C=100^o`

Freezing Pt of Water

`F=32^o`
`C=0^o`
3. Write the ratio of the two temperatures with the zero points and the size units;

`(C-0)/(100-0) = (F-32)/(212-32)`
4. Simplify the equation

`(C)/(100)=(F-32)/(180)`
5. Isolate `C` to derive the formula

`C=100/180 (F-32)`
6. Reduce fraction to lowest form
`C=(cancel(20).5)/(cancel(20).9)(F-32)`
7. The derived formula is
`C=5/9(F-32)`
8. Plug in the given value `F=230^o` to find the value in `C`
9. The answer is `C=110^o`
10. Don't really know if there is a significant difference between the two temperatures. Some say, it has approximately `1.5^o` difference between alcohol and mercury, maybe because alcohol has low boiling point compared to mercury... If so, this `230^oF` = `110^oC` for mercury-type thermometer. For alcohol-type thermometer this value is equal to `111.5^oC`.

Moreover, manufacturers probably have all types of thermometers properly calibrated such that all can give the same results...