Question

How do you solve `x^3+x^2-x=0`?

Answer 1

`1,(-1+-sqrt5)/2`

Explanation:

`x(x^2+x-1)=0`
so x=0
and
`(x^2+x-1)=0`
`x=(-1+-sqrt(1^2+4))/2=(-1+-sqrt5)/2`