How do you solve $x^{3} + x^{2} - x = 0$ $x^3+x^2-x=0$ ?

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How do you solve $x^{3} + x^{2} - x = 0$ $x^3+x^2-x=0$ ?

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Answer 1 · 2016-03-13T15:09:30

$1, \frac{- 1 \pm \sqrt{5}}{2}$ $1,(-1+-sqrt5)/2$

Explanation:

$x (x^{2} + x - 1) = 0$ $x(x^2+x-1)=0$
so x=0
and
$(x^{2} + x - 1) = 0$ $(x^2+x-1)=0$
$x = \frac{- 1 \pm \sqrt{1^{2} + 4}}{2} = \frac{- 1 \pm \sqrt{5}}{2}$ $x=(-1+-sqrt(1^2+4))/2=(-1+-sqrt5)/2$

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