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How do you solve $x^3+x^2-x=0$ ?

1 Answer

Mar 13, 2016

$1,(-1+-sqrt5)/2$

Explanation:

$x(x^2+x-1)=0$
so x=0
and
$(x^2+x-1)=0$
$x=(-1+-sqrt(1^2+4))/2=(-1+-sqrt5)/2$

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