Question

How do you find vertical, horizontal and oblique asymptotes for `y =6/x`?

Answer 1

Axes x = 0 and y = 0, in both the + and `-` directions.

Explanation:

xy = 6 represents the rectangular hyperbola, with center at (0, 0), vertices at `(sqrt6, sqrt6) and (-sqrt6, -sqrt6`).
The foci: `(sqrt12, sqrt12) and (-sqrt12, -sqrt12)`.
The eccentrictyfor a rectangular hyperbola is `sqrt2`.