Question

How do you solve `3x^3-48x=0`?

Answer 1

`x=±4`

Explanation:

`3x^3-48x=0`
`3cancel(x)^3=48cancel(x)`
`cancel(3)x^2=cancel(48)`
`x^2=16`
`sqrt(x^2)=sqrt16`
`x=±4`