Question

Question #d09d7

Answer 1

`0.20M`

Explanation:

The molarity (`C_M`) of a solute (oxalic acid) in an aqueous solution is found by:

`C_M=n/V`

where, `n` is the number of mole of oxalic acid, `V=0.250L` is the volume of the solution.

The number of mole `n` is found by: `n=m/(MM)`

where, `m=6.3g` is the mass of oxalic acid, and `MM=126g/(mol)` is the molar mass of the oxalic acid.

`=>n=m/(MM)=(6.3cancel(g))/(126cancel(g)/(mol))=0.050mol`

Thus, `C_M=n/V=(0.050mol)/(0.250L)=0.20M`

Here is a video on how to prepare a solution.
Lab Demonstration | Solution Preparation & Dilution.