Question

If `8 L` of a gas at room temperature exerts a pressure of `32 kPa` on its container, what pressure will the gas exert if the container's volume changes to `4 L`?

Answer 1

`P_2=64" " kPa`

Explanation:

`"use the Boyle's law"`
`P_1*V_1=P_2*V_2`
`32*cancel(8)=P_2*cancel(4)`
`P_2=2*32`
`P_2=64" " kPa`