How do you solve #3^(-2x+1) * 3^(-2x-3) = 3^(-x)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan Mar 15, 2016 x = #-2/3# Explanation: Use #a^m a^n = a^(m+n)#. #3^(-2x+1-2x-3) = 3^-x# Compare exponents. #-4x-2=-x# x =#-2/3#. Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 4679 views around the world You can reuse this answer Creative Commons License