How do you solve -12x^2 + 5x +2=0 using the quadratic formula?

1 Answer

x_1=-1/4" "and x_2=2/3

Explanation:

The quadratic formula is

x=(-b+-sqrt(b^2-4ac))/(2a)

Let a=-12 and b=5 and c=2

y=(-5+-sqrt((5)^2-4*(-12)*(2)))/(2(-12))

y=(-5+-sqrt(25+96))/(-24)

y=(-5+-sqrt(121))/(-24)

y_1=(-5+11)/(-24)=6/-24=-1/4

y_2=(-5-11)/(-24)=-16/(-24)=2/3

God bless.... I hope the explanation is useful.