How do you solve #abs(3-2x)= 7#?

1 Answer
Mar 17, 2016

#x=-2# or #x=5#

Explanation:

In general
#color(white)("XXX")abs(a)=b#
needs to be treated as two separate possibilities:
#color(white)("XXX")a=+bcolor(white)("XX")orcolor(white)("XX")a=-b#

Therefore, given #abs(3-2x)=7#
we have
#color(white)("XXX"){: (3-2x=+7," or ",3-2x=-7), (-2x=+4," |",-2x=-10), (x=-2," |",x=5) :}#