How do you solve #(1.5)^(3x)=7.5#?
1 Answer
Mar 17, 2016
Explanation:
#1.5^(3x)=7.5#
#log(1.5^(3x))=log(7.5)#
#(3x)log1.5=log7.5#
#3x=log7.5/log1.5#
#x=log7.5/(3log1.5)#
#color(green)(|bar(ul(color(white)(a/a)x~~1.66color(white)(a/a)|)))#