Question #3b50a

1 Answer
Mar 17, 2016

See explanation.

Explanation:

You're essentially dealing with four ionic compounds that are insoluble in aqueous solution.

Silver chloride, "AgCl"AgCl, is a white precipitate that can be obtained by mixing a solution of a soluble ionic compound that contains the silver(I) cation, "Ag"^(+)Ag+, with a solution of a soluble ionic compound that contains the chloride anion, "Cl"^(-)Cl.

http://www.drcruzan.com/Solubility.html

Lead(II) chromate, "PbCrO"_4PbCrO4, is a yellow precipitate that can be obtained by mixing a solution of a soluble ionic compound that contains the lead(II) cation, "Pb"^(2+)Pb2+, with a solution of a soluble ionic compound that contains the chromate anion, "CrO"_4^(2-)CrO24.

http://fphoto.photoshelter.com/image/I0000OuPRfDmtRvQ

Copper(II) sulfide, "CuS"CuS, is a black precipitate that can be formed by mixing a solution of a soluble ionic compound that contains the copper(II) cation, "Cu"^(2+)Cu2+, with a solution of a soluble ionic compound that contains the sulfide anion, "S"^(2-)S2.

http://fphoto.photoshelter.com/image/I0000bikDVH4iuxE

Finally, nickel(II) hydroxide, "Ni"("OH")_2Ni(OH)2, is a green precipitate that results when a solution of a soluble ionic compound that contains the nickel(II) cation, "Ni"^(2+)Ni2+, is mixed with a solution of a soluble ionic compound that contains the hydroxide anion, "OH"^(-)OH.

http://fphoto.photoshelter.com/image/I0000WDxd8SGWUcw