How do you find $| - 3 - 2 i |$ $abs(-3 - 2i )$ ?

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Answer 1 · 2016-03-18T20:16:51

$\sqrt{13}$ $sqrt(13)$

It is like the Pythagoras theorem.

$| a + b i | = \sqrt{a^{2} + b^{2}}$ $color(red)(|a +bi|=sqrt(a^2+b^2)$

$| - 3 - 2 i | = \sqrt{3^{2} + 2^{2}} = \sqrt{13}$ $|-3-2i|=sqrt(3^2+2^2)=sqrt(13)$

How do you find abs(-3 - 2i )|−3−2i|abs(-3 - 2i )?