Question

How do you convert `(6, pi/4)` to rectangular form?

Answer 1

The rectangular coordinates of `(6,pi/4)` is `3(sqrt(2),sqrt(2))`

Explanation:

Given the polar coordinates `(r,theta)=(6,pi/4)`
Find the rectangular coordinates `(x,y)`
`x=rcostheta; y=sintheta` where `r=6` and `theta = pi/4`
`x=6cos(pi/4)=3sqrt(2); y=6sin(pi/4)=3sqrt(2)`
Hence `(x,y) = (sqrt(2),sqrt(2))`