How do you solve #Log x = 5 Log 4#?

1 Answer
Mar 19, 2016

#x=1024#

Explanation:

#1#. Use the log property, #log_color(purple)bcolor(red)m^color(blue)n=color(blue)n*log_color(purple)bcolor(red)m#, to rewrite #5log4#.

#logx=5log4#

#logx=log4^5#

#2#. Since the equation now follows a "#log=log#" situation, where the bases are the same on both sides, rewrite the equation without the "log" portion.

#x=4^5#

#3#. Solve for #x#.

#color(green)(|bar(ul(color(white)(a/a)x=1024color(white)(a/a)|)))#