Question

What is the velocity `5.0 " furlongs"/"fortnight"` in `"meters"/"second"`?

Answer 1

`8.32xx10^-4 "m"/"sec"`

Explanation:

If your velocity is

`v=5.0 "furlongs"/"fortnight"`

then we'll need some conversion factors. After a quick Google search, I discovered that

`1xx"furlong" = 220 " yards"` and `1xx"fortnight"=14 " days"`

So let's get to converting! First, we may convert time:

`v=5.0 "furlongs"/"fortnight"xx(1 " fortnight")/(14 " days")`
`xx(1 " day")/(24 " hours")xx(1 " hour")/(60 " min")xx(1 " min")/(60 " sec")=4.13xx10^-6 "furlongs"/"sec"`

Second, converting distance, we have
`v=4.13xx10-6 "furlongs"/"sec"xx(220 " yards")/(1 " furlong")xx(3 " ft")/(1 " yard")`
`xx(1 " m")/(3.281 " ft")=8.32xx10^-4 "m"/"sec"`