Question

How do you write the equation of a circle with a center at (-3, -4) and a radius of 3?

Answer 1

`(x+3)^2 + (y+4)^2 =9`

Explanation:

`(x-h)^2 +(y-k)^2 = r^2`
`(x--3)^2 +(y--4)^2 = 3^2`
`(x+3)^2 + (y+4)^2 =9`

Answer 2

`(x+3)^2+(y+4)^2=9`

Explanation:

`C(a,b) "the center coordinates of circle"`
`(x-a)^2+(y-b)^2=r^2`
`"using " a=-3" "b=-4" "r=3`
`(x+3)^2+(y+4)^2=3^2`
`(x+3)^2=3^2-(y+4)^2`
`(x+3)^2+(y+4)^2=9`