Question

How do you solve `x^2-180 = 0`?

Answer 1

`x=pm6sqrt5`

Explanation:

Add `180` to both sides.

`x^2=180`

Take the square root of both sides. Recall that the positive and negative roots can be taken.

`x=pmsqrt180`

We can simplify `sqrt180` as `sqrt36*sqrt5=6sqrt5`.

`x=+-6sqrt5`

Answer 2

`x = ± 6sqrt5`

Explanation:

There are no common factors here so write as

`x^2 = 180 → x = ± sqrt180`

now require to simplify `sqrt180`

considering factors of 180 , one of which is a square.

`rArr sqrt180 = sqrt(36xx5) = sqrt36xxsqrt5 = 6sqrt5`

thus : `x = ± 6sqrt5`