Question

A container with a volume of `14 L` contains a gas with a temperature of `160^o C`. If the temperature of the gas changes to `320 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

`V_2 = 28L` the volume will double

Explanation:

Since the there is no changes in pressure you can use Charles Law which states:
`V_1/T_1 = V_2/T_2` Note this a special case of the combined Charles and Boyle Law:
`(V_1P_1)/T_1 = (V_2P_2)/T_2`, with `P_1=P_2`
Substitute and write:
`(14 L)/(160^oC) = (V_2)/(320^oC)`
`V_2 = 28L` the volume will double