Question

If a spring has a constant of `1 (kg)/s^2`, how much work will it take to compress the spring `5 cm`?

Answer 1

Here work done = PE of compressed spring =`1/2kx^2`
Given `k =1(kg)/s^2`
compression `x=5cm=0.05m`

work done = PE of compressed spring =`1/2kx^2=1/2xx1xx(0.05)^2=0.0125J`