Question

If `3 L` of a gas at room temperature exerts a pressure of `15 kPa` on its container, what pressure will the gas exert if the container's volume changes to `2 L`?

Answer 1

`P_2=22,5" "kPa`

Explanation:

`"we can solve using the Boyle's law"`
`P_1*V_1=P_2*V_2`
`3*15=P_2*2`
`45=P_2*2`
`P_2=45/2`
`P_2=22,5" "kPa`