How do you find $| 2 - 3 i |$ $abs( 2-3i )$ ?

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Answer 1 · 2016-03-25T06:55:53

$| 2 - 3 i | = 3.606$ $|2-3i|=3.606$

Finding $| 2 - 3 i |$ $|2-3i|$ means finding the modulus of complex number $2 - 3 i$ $2-3i$ .

As modulus of a complex number $a + b i$ $a+bi$ is given by $\sqrt{a^{2} + b^{2}}$ $sqrt(a^2+b^2)$

$| 2 - 3 i | = \sqrt{2^{2} + {(- 3)}^{2}} = \sqrt{4 + 9} = \sqrt{13} = 3.606$ $|2-3i|=sqrt(2^2+(-3)^2)=sqrt(4+9)=sqrt13=3.606$

How do you find |2−3i|abs( 2-3i )?