Question #9a596
1 Answer
Here is the final balanced form of the equation:
Steps are outlined below.
Explanation:
Start with this unbalanced equation:
Perhaps a simple table will help make it clearer what we need to do:
Element - Amount on the left - Amount on the right
K - 1 - 1
Mn - 1 - 1
O - 4 - 1
H - 1 - 2
Cl - 1 - 5
Clearly we need more Cl on the left, and the only place it can come from is the HCl. Let's take 5 of those:
Our table changes to:
Elmnt - Amt left - Amt right
K - 1 - 1
Mn - 1 - 1
O - 4 - 1
H - 5 - 2
Cl - 5 - 5
You can see both H and Cl changed.
Now, on the right, the only place H is going is into the
Our table changes to:
Elmnt - Amt left - Amt right
K - 1 - 1
Mn - 1 - 1
O - 4 - 5/2
H - 5 - 5
Cl - 5 - 5
You notice both H and O changed.
I dunno, though, fractions are messy. I think I'm going to multiply everything by 2 to make it clearer:
Our table changes to:
Elmnt - Amt left - Amt right
K - 2 - 2
Mn - 2 - 2
O - 8 - 5
H - 10 - 10
Cl - 10 - 10
Tricky! We need more O on the right side, so let's just go from 5 to 8 on the
Our table changes to
K - 2 - 2
Mn - 2 - 2
O - 8 - 8
H - 10 - 16
Cl - 10 - 10
OK, we fixed the O but now we have an issue with the H. Let's change the HCl on the left from 10 to 16:
Our table changes to
K - 2 - 2
Mn - 2 - 2
O - 8 - 8
H - 16 - 16
Cl - 16 - 10
Change the coefficient on the
Our table changes to
K - 2 - 2
Mn - 2 - 2
O - 8 - 8
H - 16 - 16
Cl - 16 - 16
And yay! Everything is balanced!
This is probably one of the gnarliest equations to balance, and it takes a lot of steps, but staying calm and clear makes it quite doable.