Question

What is the inverse of `log (x^2/2)-3log(x)` ?

Answer 1

`x= 10^(-y)/2`, , where y is the given function.

Explanation:

Let `y=log(x^2/2)-3 log(x)`

= `log ( x^2)+log(x^(-3))+log (2^(-1))`

= `log ((2x)^(-1))`.

Inversely, `(2x)^(-1)=10^y`. So, `x= 10^(-y)/2`