How do you solve #0.800x^2 -3.4x + 1.6 = 0#?

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Answer 1 · 2016-03-26T20:49:45

#x~~3.711" "x~~0.539# to 3 decimal places (3dp)

To make the numbers easier multiply everything by 10

#" "8x^2-34x+16=0#

This does not have whole number solutions so you need to use the formula method.

#y=ax^2+bx+c" where "x=(-b+-sqrt(b^2-4ac))/(2a)#

#x=(+34+-sqrt((-34)^2-4(8)(16)))/(2(8))#

#x=(+34+-sqrt(644))/(2(8))#

#x=(+34+-2sqrt(161))/16#

#x~~3.711" "x~~0.539# to 3 decimal places (3dp)