How do you simplify the expression #(b^3 a^5)/(b^2 a^4)#?

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Answer 1 · 2016-03-26T22:03:58

#(b^3a^5)/(b^2a^4)=ba#

Consider the example of #1/(x^3)# This may be written as #x^(-3)#

Ok, so lets look at your question. You have as the denominator :

#1/(b^2a^4)# this can be written as:#" "b^(-2)a^(-4)#

Putting this together with the numerator we have

#b^3a^5xxb^(-2)a^(-4)#

This gives us:

#b^(3-2)a^(5-4)" "=" "b^1a^1#

This is the same as:#" "ba#